Improve exception message thrown when not accepting an URL in LinkHandlerFactory#fromUrl(String url, String baseUrl)

This commit is contained in:
TobiGr 2021-05-28 14:59:35 +02:00
parent 519bba70b3
commit 858e007804
1 changed files with 7 additions and 7 deletions

View File

@ -59,19 +59,19 @@ public abstract class LinkHandlerFactory {
}
/**
* Builds a {@link LinkHandler} from a url and a base url. The url is expected to be already
* polished from google search redirects (otherwise how could {@code baseUrl} have been
* Builds a {@link LinkHandler} from an URL and a base URL. The URL is expected to be already
* polished from Google search redirects (otherwise how could {@code baseUrl} have been
* extracted?).<br>
* So do not call {@link Utils#followGoogleRedirectIfNeeded(String)} on the url if overriding
* So do not call {@link Utils#followGoogleRedirectIfNeeded(String)} on the URL if overriding
* this function, since that should be done in {@link #fromUrl(String)}.
* @param url the url without google search redirects to extract id from
* @param baseUrl the base url
* @param url the URL without Google search redirects to extract id from
* @param baseUrl the base URL
* @return a {@link LinkHandler} complete with information
*/
public LinkHandler fromUrl(String url, String baseUrl) throws ParsingException {
if (url == null) throw new IllegalArgumentException("url can not be null");
if (url == null) throw new IllegalArgumentException("URL cannot be null");
if (!acceptUrl(url)) {
throw new ParsingException("Malformed unacceptable url: " + url);
throw new ParsingException("URL not accepted: " + url);
}
final String id = getId(url);