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Fix buffer overflow in dumpNode 

The formatted string buffer doesn't need to be used, so we bypass it
with string concat
This commit is contained in:
Seth Hillbrand 2020-07-18 13:33:23 -07:00
parent 2d0e3b7e0d
commit a253c53fe7
1 changed files with 18 additions and 23 deletions
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31
common/libeval_compiler/libeval_compiler.cpp
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@ -518,8 +518,7 @@ void dumpNode( std::string& buf, TREE_NODE* tok, int depth = 0 )
if( tok->op & TR_OP_BINARY_MASK )
{
sprintf( str, "%s", (const char*) formatOpName( tok->op ).c_str() );
buf += str;
buf += formatOpName( tok->op );
dumpNode( buf, tok->leaf[0], depth + 1 );
dumpNode( buf, tok->leaf[1], depth + 1 );
}
@ -527,34 +526,30 @@ void dumpNode( std::string& buf, TREE_NODE* tok, int depth = 0 )
switch( tok->op )
{
case TR_NUMBER:
sprintf( str, "NUMERIC: " );
buf += str;
sprintf( str, "%s", formatNode( tok ).c_str() );
buf += str;
buf += "NUMERIC: ";
buf += formatNode( tok );
if( tok->leaf[0] )
dumpNode( buf, tok->leaf[0], depth + 1 );
break;
case TR_STRING:
sprintf( str, "STRING: " );
buf += str;
sprintf( str, "%s", formatNode( tok ).c_str() );
buf += str;
buf += "STRING: ";
buf += formatNode( tok );
break;
case TR_IDENTIFIER:
sprintf( str, "ID: " );
buf += str;
sprintf( str, "%s", formatNode( tok ).c_str() );
buf += str;
buf += "ID: ";
buf += formatNode( tok );
break;
case TR_STRUCT_REF:
sprintf( str, "SREF: " );
buf += str;
buf += "SREF: ";
dumpNode( buf, tok->leaf[0], depth + 1 );
dumpNode( buf, tok->leaf[1], depth + 1 );
break;
case TR_OP_FUNC_CALL:
sprintf( str, "CALL '%s': ", tok->leaf[0]->value.str );
buf += str;
buf += "CALL '";
buf += tok->leaf[0]->value.str;
buf += "': ";
dumpNode( buf, tok->leaf[1], depth + 1 );
break;
case TR_UNIT: