74 lines
2.4 KiB
C++
74 lines
2.4 KiB
C++
/*
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* This program source code file is part of KiCad, a free EDA CAD application.
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*
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* Copyright (C) 2019 KiCad Developers, see AUTHORS.TXT for contributors.
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*
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* This program is free software; you can redistribute it and/or
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* modify it under the terms of the GNU General Public License
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* as published by the Free Software Foundation; either version 2
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* of the License, or (at your option) any later version.
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*
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* This program is distributed in the hope that it will be useful,
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* but WITHOUT ANY WARRANTY; without even the implied warranty of
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* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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* GNU General Public License for more details.
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*
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* You should have received a copy of the GNU General Public License
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* along with this program; if not, you may find one here:
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* http://www.gnu.org/licenses/old-licenses/gpl-2.0.html
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* or you may search the http://www.gnu.org website for the version 2 license,
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* or you may write to the Free Software Foundation, Inc.,
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* 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301, USA
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*/
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#include <array_pad_number_provider.h>
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#include <pad.h>
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ARRAY_PAD_NUMBER_PROVIDER::ARRAY_PAD_NUMBER_PROVIDER( const FOOTPRINT* aFootprint,
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const ARRAY_OPTIONS& aArrayOpts )
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: m_arrayOpts( aArrayOpts )
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{
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// start by numbering the first new item
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m_current_pad_index = 0;
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// construct the set of existing pad numbers
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if( aArrayOpts.GetNumberingStartIsSpecified() )
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{
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// if we start from a specified point, we don't look at existing
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// names, so it's just an empty "reserved" set
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}
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else
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{
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// no footprint, no reserved names either
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if( aFootprint )
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{
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// reserve the name of each existing pad
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for( PAD* pad : aFootprint->Pads() )
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m_existing_pad_numbers.insert( pad->GetNumber() );
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}
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}
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}
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wxString ARRAY_PAD_NUMBER_PROVIDER::GetNextPadNumber()
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{
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return getNextNumber( m_current_pad_index, m_existing_pad_numbers );
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}
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wxString ARRAY_PAD_NUMBER_PROVIDER::getNextNumber( int& aIndex,
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const std::set<wxString>& aExisting )
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{
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wxString next_number;
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do
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{
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next_number = m_arrayOpts.GetItemNumber( aIndex );
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aIndex++;
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} while( aExisting.count( next_number ) != 0 );
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return next_number;
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}
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