44 lines
2.5 KiB
HTML
44 lines
2.5 KiB
HTML
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
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<html>
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<head>
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<meta http-equiv="content-type" content="text/html; charset=windows-1252"/>
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<title></title>
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<meta name="generator" content="LibreOffice 5.0.3.2 (Windows)"/>
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<meta name="created" content="00:00:00"/>
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<meta name="changed" content="2016-01-16T13:32:32.474000000"/>
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<style type="text/css">
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@page { margin: 2cm }
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p { margin-bottom: 0.25cm; line-height: 120% }
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a:link { so-language: zxx }
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</style>
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</head>
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<body lang="fr-FR" dir="ltr">
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<p style="margin-bottom: 0cm; font-style: normal; font-weight: normal; line-height: 100%">
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<font face="Times New Roman, serif"><font size="6" style="font-size: 22pt"><b>Z</b><sub><b>in</b></sub>
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desired input impedance in Ω</font></font></p>
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<p style="margin-bottom: 0cm; font-style: normal; font-weight: normal; line-height: 100%">
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<font face="Times New Roman, serif"><font size="6" style="font-size: 22pt"><b>Z</b><sub><b>out</b></sub><sub>
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</sub> desired output impedance in Ω</font></font></p>
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<p style="margin-bottom: 0cm; font-style: normal; font-weight: normal; line-height: 100%">
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<font face="Times New Roman, serif"><font size="6" style="font-size: 22pt">a
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attenuation in dB</font></font></p>
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<p style="margin-bottom: 0cm; font-style: normal; font-weight: normal; line-height: 100%">
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<font face="Times New Roman, serif"><font size="6" style="font-size: 22pt">L
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= 10<sup>a/10</sup> (the loss)</font></font></p>
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<p style="margin-bottom: 0cm; font-style: normal; font-weight: normal; line-height: 100%">
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<font face="Times New Roman, serif"><font size="6" style="font-size: 22pt">A
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= (L + 1)/(L − 1)</font></font></p>
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<p style="margin-bottom: 0cm; font-style: normal; font-weight: normal; line-height: 100%">
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<br/>
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</p>
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<p style="margin-bottom: 0cm; font-style: normal; line-height: 100%"><font face="Times New Roman, serif"><font size="6" style="font-size: 28pt"><b>Pi
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attenuator</b></font></font></p>
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<p style="margin-bottom: 0cm; line-height: 100%"><font face="Times New Roman, serif"><font size="6" style="font-size: 28pt"><i><b>R2
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= (L − 1)/2 * √ ((Z<sub>in</sub> * Z<sub>out</sub>)/L)</b></i></font></font></p>
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<p style="margin-bottom: 0cm; line-height: 100%"><font face="Times New Roman, serif"><font size="6" style="font-size: 28pt"><i><b>R1
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= 1/( A/Z<sub>in</sub> − 1/R2)</b></i></font></font></p>
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<p style="margin-bottom: 0cm; line-height: 100%"><font face="Times New Roman, serif"><font size="6" style="font-size: 28pt"><i><b>R3
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= 1/ (A/Z<sub>out</sub> − 1/R2)</b></i></font></font></p>
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</body>
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</html> |